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feat: add solutions to lc problem: No.0255
No.0255.Verify Preorder Sequence in Binary Search Tree
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‎solution/0200-0299/0255.Verify Preorder Sequence in Binary Search Tree/README.md‎

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@@ -32,27 +32,100 @@
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<p>您能否使用恒定的空间复杂度来完成此题？</p>
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## 解法
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<!-- 这里可写通用的实现逻辑 -->
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二叉搜索树先序遍历时，每次移向左子树时，值递减，移向右子树时，值递增。
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因此，可以维护一个单调递减栈。遍历序列，若当前值大于栈顶元素，说明开始要进入右子树的遍历。只要栈顶元素比当前值小，就表示还是左子树，要移除，也就是从栈中弹出，直至栈顶元素大于当前值，或者栈为空。此过程要记录弹出栈的最后一个元素 last。
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接下来继续往后遍历，之后右子树的每个节点，都要比 last 大，才能满足二叉搜索树，否则直接返回 false。
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<!-- tabs:start -->
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### **Python3**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```python
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class Solution:
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def verifyPreorder(self, preorder: List[int]) -> bool:
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stk = []
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last = float('-inf')
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for x in preorder:
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if x < last:
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return False
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while stk and stk[-1] < x:
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last = stk.pop()
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stk.append(x)
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return True
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```
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### **Java**
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<!-- 这里可写当前语言的特殊实现逻辑 -->
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```java
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class Solution {
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public boolean verifyPreorder(int[] preorder) {
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Deque<Integer> stk = new ArrayDeque<>();
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int last = Integer.MIN_VALUE;
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for (int x : preorder) {
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if (x < last) {
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return false;
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}
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while (!stk.isEmpty() && stk.peek() < x) {
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last = stk.poll();
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}
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stk.push(x);
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}
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return true;
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}
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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bool verifyPreorder(vector<int>& preorder) {
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stack<int> stk;
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int last = INT_MIN;
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for (int x : preorder)
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{
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if (x < last) return false;
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while (!stk.empty() && stk.top() < x)
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{
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last = stk.top();
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stk.pop();
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}
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stk.push(x);
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}
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return true;
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}
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};
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```
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### **Go**
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```go
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func verifyPreorder(preorder []int) bool {
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var stk []int
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last := math.MinInt32
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for _, x := range preorder {
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if x < last {
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return false
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}
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for len(stk) > 0 && stk[len(stk)-1] < x {
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last = stk[len(stk)-1]
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stk = stk[0 : len(stk)-1]
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}
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stk = append(stk, x)
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}
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return true
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}
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```
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### **...**

‎solution/0200-0299/0255.Verify Preorder Sequence in Binary Search Tree/README_EN.md‎

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<p>&nbsp;</p>
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<p><strong>Follow up:</strong> Could you do it using only constant space complexity?</p>
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## Solutions
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<!-- tabs:start -->
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### **Python3**
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```python
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class Solution:
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def verifyPreorder(self, preorder: List[int]) -> bool:
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stk = []
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last = float('-inf')
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for x in preorder:
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if x < last:
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return False
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while stk and stk[-1] < x:
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last = stk.pop()
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stk.append(x)
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return True
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```
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### **Java**
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```java
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class Solution {
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public boolean verifyPreorder(int[] preorder) {
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Deque<Integer> stk = new ArrayDeque<>();
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int last = Integer.MIN_VALUE;
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for (int x : preorder) {
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if (x < last) {
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return false;
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}
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while (!stk.isEmpty() && stk.peek() < x) {
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last = stk.poll();
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}
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stk.push(x);
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}
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return true;
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}
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}
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```
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### **C++**
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```cpp
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class Solution {
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public:
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bool verifyPreorder(vector<int>& preorder) {
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stack<int> stk;
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int last = INT_MIN;
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for (int x : preorder)
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{
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if (x < last) return false;
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while (!stk.empty() && stk.top() < x)
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{
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last = stk.top();
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stk.pop();
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}
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stk.push(x);
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}
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return true;
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}
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};
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```
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### **Go**
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```go
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func verifyPreorder(preorder []int) bool {
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var stk []int
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last := math.MinInt32
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for _, x := range preorder {
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if x < last {
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return false
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}
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for len(stk) > 0 && stk[len(stk)-1] < x {
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last = stk[len(stk)-1]
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stk = stk[0 : len(stk)-1]
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}
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stk = append(stk, x)
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}
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return true
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}
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```
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### **...**

‎solution/0200-0299/0255.Verify Preorder Sequence in Binary Search Tree/Solution.cpp‎

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class Solution {
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public:
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bool verifyPreorder(vector<int>& preorder) {
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stack<int> stk;
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int last = INT_MIN;
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for (int x : preorder)
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{
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if (x < last) return false;
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while (!stk.empty() && stk.top() < x)
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{
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last = stk.top();
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stk.pop();
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}
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stk.push(x);
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}
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return true;
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}
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};

‎solution/0200-0299/0255.Verify Preorder Sequence in Binary Search Tree/Solution.go‎

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func verifyPreorder(preorder []int) bool {
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var stk []int
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last := math.MinInt32
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for _, x := range preorder {
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if x < last {
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return false
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}
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for len(stk) > 0 && stk[len(stk)-1] < x {
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last = stk[len(stk)-1]
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stk = stk[0 : len(stk)-1]
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}
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stk = append(stk, x)
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}
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return true
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}

‎solution/0200-0299/0255.Verify Preorder Sequence in Binary Search Tree/Solution.java‎

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@@ -0,0 +1,16 @@
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class Solution {
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public boolean verifyPreorder(int[] preorder) {
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Deque<Integer> stk = new ArrayDeque<>();
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int last = Integer.MIN_VALUE;
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for (int x : preorder) {
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if (x < last) {
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return false;
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}
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while (!stk.isEmpty() && stk.peek() < x) {
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last = stk.poll();
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}
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stk.push(x);
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}
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return true;
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}
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}

‎solution/0200-0299/0255.Verify Preorder Sequence in Binary Search Tree/Solution.py‎

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class Solution:
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def verifyPreorder(self, preorder: List[int]) -> bool:
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stk = []
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last = float('-inf')
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for x in preorder:
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if x < last:
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return False
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while stk and stk[-1] < x:
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last = stk.pop()
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stk.append(x)
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return True

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