Update RawFileInput.scala

trying to fix bug where name appears blank

Author: kmader

core/src/main/scala/org/apache/spark/input/RawFileInput.scala

@@ -61,16 +61,22 @@ abstract class StreamFileInputFormat[T]
  */
 class PortableDataStream(split: CombineFileSplit, context: TaskAttemptContext, index: Integer)
   extends Serializable {
-  private var path = ""
+
   private var fileIn: FSDataInputStream = null.asInstanceOf[FSDataInputStream]
   private var isOpen = false
+  /**
+   * Calculate the path name independently of opening the file
+   */
+  private lazy val path = {
+    val pathp = split.getPath(index)
+    path = pathp.toString
+  }
 
   /**
    * create a new DataInputStream from the split and context
    */
   def open(): FSDataInputStream = {
     val pathp = split.getPath(index)
-    path = pathp.toString
     val fs = pathp.getFileSystem(context.getConfiguration)
     fileIn = fs.open(pathp)
     isOpen=true
@@ -126,9 +132,9 @@ abstract class StreamBasedRecordReader[T](
   override def nextKeyValue = {
     if (!processed) {
       val fileIn = new PortableDataStream(split,context,index)
-      key = fileIn.getPath
       value = parseStream(fileIn)
       fileIn.close() // if it has not been open yet, close does nothing
+      key = fileIn.getPath
       processed = true
       true
     } else {