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More convenient syntax for getting the size of a block #369

@mtfishman

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@mtfishman

New syntax proposal for obtaining the size of a block

EDIT: TLDR: This proposal is to change the definition of blocksizes so that it acts like this:

julia> using BlockArrays

julia> a = BlockArray(randn(5, 5), [2, 3], [2, 3])
2×2-blocked 5×5 BlockMatrix{Float64}:
  0.916747   1.451410.740126    0.663479  0.17119 
 -0.563452   0.5749730.618916   -1.43895   1.40107 
 ──────────────────────┼─────────────────────────────────
  0.621363   2.863330.0611178  -0.928277  1.48074 
  0.106673  -0.673614-1.49219     0.158793  0.564433
  0.017256  -1.108240.768847    0.923508  0.362625

julia> blocksizes(a)[1, 2]
(2, 3)

julia> blocksizes(a)
2×2 BlockSizes{2, BlockMatrix{Float64, Matrix{Matrix{Float64}}, Tuple{BlockedUnitRange{Vector{Int64}}, BlockedUnitRange{Vector{Int64}}}}}:
 (2, 2)  (2, 3)
 (3, 2)  (3, 3)

i.e. it acts like a collection of size blocksize(a), and indexing into it outputs the size of the corresponding block.

The current definition gives:

julia> blocksizes(a)
([2, 3], [2, 3])

which is equivalent to:

julia> blocklengths.(axes(a))
([2, 3], [2, 3])

so uses of the current blocksizes definition could switch to that, which I think is clearer anyway. See also the discussion in #255.

Summary of the current syntax for obtaining the size of a block

From what I can tell, these are the most compact ways of getting the size of a block right now, using public APIs:

julia> using BlockArrays

julia> a = BlockArray(randn(5, 5), [2, 3], [2, 3])
2×2-blocked 5×5 BlockMatrix{Float64}:
  0.916747   1.451410.740126    0.663479  0.17119 
 -0.563452   0.5749730.618916   -1.43895   1.40107 
 ──────────────────────┼─────────────────────────────────
  0.621363   2.863330.0611178  -0.928277  1.48074 
  0.106673  -0.673614-1.49219     0.158793  0.564433
  0.017256  -1.108240.768847    0.923508  0.362625

julia> size(view(a, Block(1, 2)))
(2, 3)

julia> size(@view(a[Block(1, 2)]))
(2, 3)

julia> getindex.(blocksizes(a), Int.(Tuple(Block(1, 2))))
(2, 3)

julia> getindex.(blocksizes(a), Int.((Block(1), Block(2))))
(2, 3)

julia> getindex.(blocksizes(a), (1, 2))
(2, 3)

julia> length.(getindex.(axes(a), Tuple(Block(1, 2))))
(2, 3)

julia> getindex.(blocklengths.(axes(a)), Int.(Tuple(Block(1, 2))))
(2, 3)

(please correct me if I am wrong).

I think it would be nice to have something more convenient. The best I can come up with is overloading Base.size(a::AbstractArray, b::Block), for example:

julia> Base.size(a::AbstractArray{<:Any,N}, b::Block{N}) where {N} = size(@view(a[b]))

julia> size(a, Block(1, 2))
(2, 3)

It feels like a slight abuse of Base.size, but seems along the same lines as being able to ask for the size in a certain dimension with size(a, 1).

I believe this would make sense for getting the axes of a block as well, i.e. axes(a, Block(1, 2)), however perhaps there is some ambiguity there if that is meant to be a slice of the axes of a, i.e.:

julia> getindex.(axes(a), Tuple(Block(1, 2)))
(1:2, 3:5)

or the axes of the @view(a[Block(1, 2)]), i.e.:

julia> only.(axes.(getindex.(axes(a), Tuple(Block(1, 2)))))
(Base.OneTo(2), Base.OneTo(3))

It is a bit unfortunate that blocksize is already taken and has a different meaning, I understand why that choice was made but I found that to be confusing at first and my initial thought was that it should be a way to get the size of a block.

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