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@KristofferC KristofferC commented Jun 20, 2018

Before:

julia> @btime string("foo", 'b', "ar")
  443.838 ns (8 allocations: 288 bytes)

After

julia> @btime string("Foo", 'b', "ar")
  110.836 ns (3 allocations: 192 bytes)

Ref #27030 (comment)

@KristofferC KristofferC added performance Must go faster strings "Strings!" labels Jun 20, 2018
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@nanosoldier runbenchmarks("shootout" || "string" || "problem", vs=":master")

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KristofferC commented Jun 21, 2018

This is still 3x slower than 0.6 though (instead of 12).

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Your benchmark job has completed - no performance regressions were detected. A full report can be found here. cc @ararslan

@KristofferC KristofferC reopened this Jun 22, 2018
for x in a
print(io, x)
end
return String(resize!(io.data, io.size))
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Why not String(take!(io))?

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This consumes the data rather than making a copy.

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@mbauman mbauman Jun 22, 2018

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In this case, take! behaves the same way and doesn't make a copy. Ah, but I do understand now, the issue is that take! also is preparing the IOBuffer for additional writes, and allocates a new buffer to replace the one that becomes the string.

In Kristoffer's @btime string("foo", 'b', "ar"), this incurs a 30% penalty. Alright, carry on.

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I wish take! didn't do that. In the vast majority (all?) of cases, an IOBuffer is not used after take! is called, so we should at least optimize for that case.

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Opened #27741

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6 participants