inference: override InterConditional result with Const carefully
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aviatesk
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I found that a tricky thing can happen when constant inference derives `Const`-result while non-constant inference has derived (non-constant) `InterConditional` result beforehand. In such a case, currently we discard the result with constant infernece (since `!(Const ⊑ InterConditional)`), but we can achieve more accuracy by not discarding that `Const`-information, e.g.: ```julia julia> iszero_simple(x) = x === 0 iszero_simple (generic function with 1 method) julia> @test Base.return_types() do iszero_simple(0) ? nothing : missing end |> only === Nothing Test Passed ```
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vtjnash
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Mar 20, 2022
KristofferC
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Mar 20, 2022
Co-authored-by: Kristoffer Carlsson <[email protected]>
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aviatesk
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…44668) I found that a tricky thing can happen when constant inference derives `Const`-result while non-constant inference has derived (non-constant) `InterConditional` result beforehand. In such a case, currently we discard the result with constant inference (since `!(Const ⊑ InterConditional)`), but we can achieve more accuracy by not discarding that `Const`-information, e.g.: ```julia julia> iszero_simple(x) = x === 0 iszero_simple (generic function with 1 method) julia> @test Base.return_types() do iszero_simple(0) ? nothing : missing end |> only === Nothing Test Passed ```
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I found that a tricky thing can happen when constant inference derives
Const-result while non-constant inference has derived (non-constant)InterConditionalresult beforehand. In such a case, currently we discardthe result with constant infernece (since
!(Const ⊑ InterConditional)),but we can achieve more accuracy by not discarding that
Const-information, e.g.: