Is it possible to hide menus and submenus based on a select?

[safiro]

I've over 10 menus with too much fields and it takes too much time to load.
So, I created array in global options menu:

             'title'=>'Choose your theme',
    'id'=>'picklayout',
    'type'=>'select',

    'options'=>array(
    'layoutone'=>'Layout One',
    'layouttwo'=>'Layout Two',
            'layoutthree'=>'Layout Three',
    'layoutfour'=>'Layout Four',
    'layoutfive'=>'Layout Five',
            'layoutsix'=>'Layout Six',
    ),
    'default'=>'layoutthree',
    ),

Now, I'd like when theme activated, all menus not displayed but only layout three menu, if I select Layout Two and refresh , only layout two options menu displayed. and so on ......

Thanks.

[kprovance]

Unfortunately, this issue tracker is for bug reports. This kind of thing would fall under premium support, since it's not a bug or an issue with Redux. Here is a hint however: Use the compiler hook. https://docs.reduxframework.com/core/advanced/integrating-a-compiler/ Sample included in the sample-config.php

[safiro]

I think it can be done but I want to know how to get the array output inside sample-config.php
for WP files we use
global $opt_name;
$layout = $opt_name['picklayout'];

How to do this in sample-config.php before Redux::setSection($opt_name,array( ???
I think I can do it by using if statement but I need to get the array output.

[kprovance]

Redux::getOption (opt_name, opt_id)

It's newly added, not in the docs yet.

[safiro]

How to use it?
In sample-config.php What's the code for:
if (picklayout value == 'two'){
run the code.
}